Hello. Greetings to all.
I have two K40 machines that I’m putting the MKS 32 board on and this is the schematic I made for each power supply, according to the forums.
I don’t want to try until I’m sure it’s okay so as not to break the motherboard, and I’d like to know if I can add the 10K potentiometer.
Thank you very much
Which supply are you going to use? The left one is usually used in a K40, the top is used most for most of the larger hobby lasers.
In either case, the pwm output of the DLC32 is out of the top right connector and labeled signal, center is ground and the last is the 12/24V supply for the laser module.
To the top lps, it’s correct, but it’s wired to ground at the other lps.
If you’re thinking that spindle - is a ground connection, it’s not wired that way. The spindle - goes through a mosfet that is switched to ground when the pwm cycle goes high. This is the pcb and shows the location of J18 and J7.
Spindle - is J7-1 and is J18-3 is pwm output for the laser module. Note that the pwm just turns on Q1, completing the circuit to ground. This isn’t for a ground it’s for the cathode lead to the spindle motor.
Not normally the way they do that with pwm driving the IN pin. They use the pwm input and apply a dc voltage to it (developed across the console pot). The pwm is now turning the tube on/off at whatever power is set on the IN pin.
If you get the top supply, those usually have a pot inside to adjust maximum current limiting. If that’s set correctly, then 100% power in Lightburn will result in the maximum current you’ve set. You can’t overdrive the tube.
You might want to check out the supply current from the top supply… It looks like mine, but when I zoom in, it’s too blurry for these old eyes.
Good luck
Thank you very much for your attention. Please excuse my English, it is a direct translation from Google
I understood 60%, that is, I remove the connection from connector J7 to J18. The image of connector J18 is to a diode laser? In the power source it would be (IN in S) (G in TTL) (5v in V).
How can I set the Lightbunr to 100% at 15mA?
PWM comes out as S, G is ground and the V would be the boards supply voltage. What you’re doing doesn’t require anything but the pwm signal and maybe ground.
You have to set the percent power to 50% in Lightburn then adjust internal pot of the lps to 50% of the current you want, in your case you want 15mA, so your target is 7.5mA. Once you’ve done this, then 100% power will relate to 15mA.
Make sense?
The lps on the left in your diagram doesn’t have a way to adjust the maximum current source…
Si entiendo. al regresar del trabajo probare, muchísimas gracias
Yes, I understand. I will try it when I get back from work. Thank you very much.
Hello! That sounds like an exciting upgrade. It’s great that you’re being cautious before testing. If your schematic follows the forum guidelines, it should be fine, but double-checking is always a good idea. As for the 10K potentiometer, it depends on how you plan to use it in the circuit—some setups may require specific wiring to avoid issues. Maybe sharing the schematic could help others give better feedback. Good luck with your project! 
There are at least two ways of wiring this up. Are you using a console mounted pot to adjust current?
Post 2, explains most of this.
As you can see, the pinout of the module is S (signal or pwm) TTL is actually above the ground pin (center). The module power supply is V, this is the board supply is not 5V, it’s either 12 or 24V.
- pot controls current level and the laser is turned on/off with the pwm signal
- pwm goes to IN of the lps and L is used to enable the laser.
Which way are you going to do it?
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